3x=0.25x^2+5

Solution for 3x=0.25x^2+5 equation:

3x=0.25x^2+5

We move all terms to the left:

3x-(0.25x^2+5)=0

We get rid of parentheses

-0.25x^2+3x-5=0

a = -0.25; b = 3; c = -5;
Δ = b2-4ac
Δ = 32-4·(-0.25)·(-5)
Δ = 4
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{4}=2$
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(3)-2}{2*-0.25}=\frac{-5}{-0.5}
=+10
$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(3)+2}{2*-0.25}=\frac{-1}{-0.5}
=+2
$